Solved thermodynamics exercise
Changing the size of a system
Exercise 7 · Lesson 3 — Fundamental Concepts
- extensivity
- intensivity
- homogeneity
- surface
- dimensional analysis
Statement
An ordinary homogeneous system has mass , volume , particle number , internal energy , temperature and pressure . We assume here that is extensive, long-range interactions and edge effects being neglected. Its size is changed at fixed intensive state: , with , while and remain unchanged.
- Determine the degree of homogeneity of , , , , and . Which quantities are extensive, which are intensive, and which are neither?
- Two expressions are proposed for an energy: and , where is dimensionless and independent of the size of the system. Check their dimensions, then determine which one is consistent with the extensivity assumption. Explain why these two checks are distinct.
- For a sphere of radius , express the area in terms of the volume . Determine the degrees of homogeneity of and when a single sphere is enlarged at fixed density.
- Compare the area of a sphere of volume with the total area of eight separate spheres, each of volume . Explain why “enlarging an object” and “juxtaposing copies” do not give the same result for the area of its interfaces.
Hint
Detailed solution
These three ratios are of degree and hence intensive. Next, Thus and are of degree , and hence extensive in the sense of the given scaling law; is of degree , and is therefore neither extensive nor intensive. The degree of homogeneity says nothing about units: is expressed in joules, but in . Only is consistent with the assumed extensivity. A formula can therefore have the correct units and yet depend incorrectly on the size of the system. This does not rule out every non-extensive energy: it is the assumption made in this exercise that excludes . Hence : the area is of degree . Dividing by gives . The surface-to-volume ratio is of degree and decreases as the sphere grows.